Comments on: How to get a path and extension from a file http://www.sapflow.cz/archives/190 Anything can be done, it's just a matter of time and money... Wed, 23 Nov 2011 20:49:32 +0000 hourly 1 By: Pavel Jaroš http://www.sapflow.cz/archives/190/comment-page-1#comment-3642 Pavel Jaroš Thu, 01 Oct 2009 12:42:47 +0000 http://www.sapflow.cz/?p=190#comment-3642 Unfortunately it's not the perfect way how to parse file name. For example for the file "test.01.xml" it returns extension 01.xml and it's not correct. What's about something like this? DATA: lt_split TYPE string OCCURS 0 WITH HEADER LINE, l_file(100) TYPE c VALUE 'test.01.xml'. SPLIT l_file AT '.' INTO TABLE lt_split. LOOP AT lt_split. ENDLOOP. WRITE: / 'Extension:', lt_split. It should be better. Unfortunately it’s not the perfect way how to parse file name.
For example for the file “test.01.xml” it returns extension 01.xml and it’s not correct.

What’s about something like this?

DATA: lt_split TYPE string OCCURS 0 WITH HEADER LINE,
l_file(100) TYPE c VALUE ‘test.01.xml’.

SPLIT l_file AT ‘.’ INTO TABLE lt_split.

LOOP AT lt_split.
ENDLOOP.

WRITE: / ‘Extension:’, lt_split.

It should be better.

]]>